# Kinetic friction of crate being pulled

I've worked this problem an dget an answer, but when i enter it into our homework site, it says my answer of 229 N is wrong, do any of you see what im doing wrong.
A 1.06×102 kg crate is being pulled across a horizontal floor by a force P that makes an angle of 28.9° above the horizontal. The coefficient of kinetic friction is 0.193. What should be the magnitude of P, so that the net work done by it and the kinetic frictional force is zero?

I found the force applied by friction to be 200.5 N (F= (0.193)(106kg)(9.8m/s2)

so to find the force of P i said the force in the opposite x direction needs to be equal to the frictional force

cos28.9= 200.49/P

=229 N

If you see anything I'm doing wrong or another way to approach it tell me.

I don't think this is suppose to be a difficult problem.

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OlderDan
Homework Helper
jp04 said:
I've worked this problem an dget an answer, but when i enter it into our homework site, it says my answer of 229 N is wrong, do any of you see what im doing wrong.
A 1.06×102 kg crate is being pulled across a horizontal floor by a force P that makes an angle of 28.9° above the horizontal. The coefficient of kinetic friction is 0.193. What should be the magnitude of P, so that the net work done by it and the kinetic frictional force is zero?

I found the force applied by friction to be 200.5 N (F= (0.193)(106kg)(9.8m/s2)

so to find the force of P i said the force in the opposite x direction needs to be equal to the frictional force

cos28.9= 200.49/P

=229 N

If you see anything I'm doing wrong or another way to approach it tell me.

I don't think this is suppose to be a difficult problem.