An Olympic skier moving at 28 m/s down a 24 degrees slope encounters a region of snowless ground of coefficient of kinetic friction 0.67. The acceleration of gravity is 9.8 m/s^2 How far down the slope does she travel before coming to a halt? Answer in units of m. I came up with an equation of: mgsin(theta) - Fk*d = ma I would solve for "d" but i'm not sure how to get the "a". help appreciated. TIA.