A rescue worker pulls an injured skier lying on a toboggan (with a combined mass of 127 kg) across flat snow at a constant speed. A 2.43 m rope is attached to the toboggan at ground level, and the rescuer holds the rope taut at shoulder level. If the rescuer's shoulders are 1.65 m above the ground, and the tension in the rope is 148 N, what is the coefficient of kinetic friction between the toboggan and the snow? I have two questions about this problem. Is the net force of the toboggan = Tension force - Friction force = ma = 0 ?? Is the Rope tension force = 148*cos(arcsin(1.65/2.43)) ?? I dont know if Im reading the problem about the rope part wrong . Should we be using trigonometry here?