1. The problem statement, all variables and given/known data An electric motor is used to pull a 125kg box across a floor using a long cable. The tension in the cable is 350N and the box accelerates at 1.2 m/s/s [fwd] for 5.0s. The cable breaks and the box slows down and stops a )Calculate the coefficient of kinetic friction. [ans:0.16] b) How far does the box travel up to the moment the cable breaks? [ans: 15m] c) How far does the box travel from the moment the cable breaks until it stops? [ans: 11m] 2. Relevant equations Kinematics equations 3. The attempt at a solution Ft-Fk=ma 350-Fk=(125)(1.2) Fk=200N μk=Fk/Fn =200/(125)(9.8) μk=0.16 b) D=Vft-1/2at^2 = 0-1/2(-1.2)(5)^2 = 15m c) I know my solution for b) is correct. But I don't understand why the Vf is zero when the cable breaks because shouldn't the Vf be zero when the box actually comes to a stop and not when the cable breaks. Assuming I solved b) correct, and Vf = 0 then how would I solve c) when the box actually comes to a stop?