Sir, Please help me with this problem. # A fixed mass of gas at constant pressure occupies a volume V. The gas undergoes a rise in temperature so that the root mean squared velocity(c) of the molecule is doubled. What is the new volume? I solved it in the following way:- Let V1 be the initial volume & V2 be the final volume. Assuming the pressure to be constant, c = (3PV1/M)^1/2 --------- (1) 2c = (3PV2/M)^1/2 --------- (2) Dividing equation (1) by (2) we get, ½ = (V1/V2)^1/2 Squaring on both sides we get, ¼ = (V1/V2) V2 = 4V1 But the answer given in my book is V2 = V1/[(2)^1/2] read as V1 divided by root 2.Here the symbol ^ represents power.