The rms speed of the molecules in a gas is 600ms^-1 and the mass of the molecules is 4.6*10^-26kg. What is the temperature of the gas in degrees Celcius?(adsbygoogle = window.adsbygoogle || []).push({});

[tex]

v_{r.m.s.}\=\600\ms^-1 \\

m\=\4.6x10^-26kg \\

n\=\6.022x10^23 \\

r\=8.31\j\k\mol^-1 \\

\\

\\

rt\=\frac{\2}{3}\(\frac{\1}{2}m<v^2>)\\

t\=\frac{\frac{\2}{3}\(\frac{\1}{2}m<v^2>)}{r}\\

t\=\frac{\frac{\2}{3}\(\frac{\1}{2}\x\4.6x10^-26\x\600^2)}{8.31}\\

t\=\frac{3324.14}{8.31}\\

t\=\400K\\

t(c)\=\400-273\=\127c\\

[/tex]

Does this seem correct? I have no way of checking the answer and I feel really unsure, especially using the Vr.m.s.

Thanks

EDIT: I can't understand why my TEX doesn't work :(

My tex code:

V_{r.m.s.}\=\600\ms^-1 \\

m\=\4.6x10^-26kg \\

N\=\6.022x10^23 \\

R\=8.31\J\K\mol^-1 \\

\\

\\

RT\=\frac{\2}{3}\(\frac{\1}{2}m<v^2>)\\

T\=\frac{\frac{\2}{3}\(\frac{\1}{2}m<v^2>)\\}{R}\\

T\=\frac{\frac{\2}{3}\(\frac{\1}{2}\x\4.6x10^-26\x\600)\\}{8.31}\\

T\=\frac{3324.14}{8.31}\\

T\=\400K\\

T(C)\=\400-273\=\127C\\

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# Kinetic Theory Of Temperature Problem

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