1. The problem statement, all variables and given/known data a 3.5 Mg engine is suspended from a spreader beam having a negligible mass and is hoisted by a crane which exerts a force of 40kN on the hoisting cable. determine the distance the engine is hoisted in 4 s starting from rest. 2. Relevant equations f=ma vf^2 = vi^2 + 2ad v=Vo + at 3. The attempt at a solution first i used f=ma converted force of 40kN to N so 40000 and converted 3.5 Mg to kg so 3500 then a = f/m so a = 11.4286 m/s^2 (this seems to high but i continued anyways) then i took v= Vo +at Vo=0 a is from above and t = 4s just plug in and you get 45.71 m/s then use vf^2 = vi^2 + 2ad vf = 45.71 vi = 0 a = 11.43 solve for d and you get something like 91m that i know is wrong. i should get something like 13 m does anyone see where im going wrong??