(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

http://rgoth.com/q18.gif [Broken]

2. The attempt at a solution

I followed Kirchoff's Rules for part A of this question by outlining three formulas. Each starts at point A on the diagram

-(6)I1 + 18 - (6)I1 + 8 - (22)I3

I3 = [-26 +(12)I1]/-22 ******formula 1

-(6)I1 +18 -(6)I1 - (14)I2 = 0

I2 = [-30 + (12)I1]/-14 *****formula 2

I1 = I2 + I3 *******formula 13

By combining these three formulas I solved for I1 and used that to find I2 by using formula #2

My final answer is 0.96 amp

Because this is positive it means I chose the right direction for my current with my original formulas. Therefore the current is flowing counter clockwise in the circuit... Is that right?

does this look right. I have never done a question with three batteries of which one is facing the opposite way to the others...

for part b do I just add each emf to find the voltage across ab

ie

12V - 8V + 18v = 22V

I minus because it faces the opposite direction as the 12 V emf

I don't think this looks right at all but I am unsure where to go.

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# Kirchhhoffs rule

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