1. The problem statement, all variables and given/known data http://rgoth.com/q18.gif [Broken] 2. The attempt at a solution I followed Kirchoff's Rules for part A of this question by outlining three formulas. Each starts at point A on the diagram -(6)I1 + 18 - (6)I1 + 8 - (22)I3 I3 = [-26 +(12)I1]/-22 ******formula 1 -(6)I1 +18 -(6)I1 - (14)I2 = 0 I2 = [-30 + (12)I1]/-14 *****formula 2 I1 = I2 + I3 *******formula 13 By combining these three formulas I solved for I1 and used that to find I2 by using formula #2 My final answer is 0.96 amp Because this is positive it means I chose the right direction for my current with my original formulas. Therefore the current is flowing counter clockwise in the circuit... Is that right? does this look right. I have never done a question with three batteries of which one is facing the opposite way to the others... for part b do I just add each emf to find the voltage across ab ie 12V - 8V + 18v = 22V I minus because it faces the opposite direction as the 12 V emf I don't think this looks right at all but I am unsure where to go.