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1. The problem statement, all variables and given/known data

Suppose we have the circuit as in the diagram where the potential on the capacitor islargerthan that on the battery.

ie. [tex]V_c>V_b[/tex]

What is Kirchhoff's 2nd law for the circuit?

2. The attempt at a solution

[tex]V_b+IR-\frac{V_c}{C}=0[/tex]

My reasoning is as follows:

--going in a clockwise direction

[tex]+V_b[/tex] -- since taking positive charge from cathode(-) to diode(+) would add to the potential

[tex]+IR[/tex] -- since we are moving against the direction of current (ie. clockwise)

[tex]-V_c /C[/tex] -- since taking a positve charge from the top plate to the bottom plate would reduce the potential on the capacitor

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# Homework Help: Kirchhoffs 2nd for Capacitor

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