- #1
Janiceleong26
- 276
- 4
Homework Statement
For part (iv) 2 and 3 of this question, I don't understand why for 2) terminal p.d. of A is the e.m.f of A minus the p.d. across the internal resistance of A i.e. Va = 4.4-(0.24x2.3), I=0.24A
But for 3) the terminal p.d. is the e.m.f of B PLUS the p.d. across the internal resistance of B i.e. Vb= 2.1+(1.8x0.24)
Homework Equations
ΣE.m.f = Σp.d. around a closed circuit
The Attempt at a Solution
I minus the p.d. across the internal resistance to the e.m.f. for both cases. I can't to seem to see why is this wrong..