I am confused with explanation about Kirchhoff's law in LC circuit. Please refer to the file I attached for the LC circuit. First, the switch was connected to the emf and the capacitor was charged to its full capacitance. Then the switch is connected to the capacitor, the capacitor will start to discharge clockwise. Let me trace the closed loop clockwise and sum all of the voltage differences. Then I get (q/c) - L(dI/dt) = 0 for the Kirchhoff's second law, because I trace the capacitor from its cathode to anode and the inductor will opposite the current. But common textbooks says that (q/c) + L(dI/dt) = 0 with no thorough explanation. What am I missing for this issue?