In the following figure(Figure 1) the battery has emf 26.0V and negligible internal resistance. R1 = 4.10Ω . The current through R1 is 1.50A and the current through R3 = 5.00A
What are the resistances of R2 and R3?
Kirchoff's Loop/Junction Rule
The Attempt at a Solution
I am having some real problems with Kirchoff's Rules. Can someone help me figure out how to begin? I started out by saying that Since the current through R3 is 5A, then that is the same as the current that gets split at the junction into I_1 through R_1 and I_2 through R_2. Also, I know that the voltage drop across R_1 is equal to the voltage drop across R_2 which is 6.15V. Using this, I said that (R_2)(I_2)=6.15V. I was given I_1 (the current through R_1) and I believe the current that enters the junction is the 5A that were given in the problem that go through R_3. Using that, I said that I_2 + I_1 = 5A. Knowing I_1, I found that I_2 should be .9A, which would make R2=6.833 Ohms. I don't know if this is right. Even if it is, how do I go about solving for R_3? I am very confused. Any help would be great.
4.6 KB Views: 789