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Kirchoff's Law

  1. Oct 26, 2008 #1
    1. The problem statement, all variables and given/known data

    A Wheatstone Bridge with 5 resistors

    http://img529.imageshack.us/my.php?image=physicsproblemmo7.png

    2. Relevant equations

    Use Kirchoff's Law

    3. The attempt at a solution

    I know that I have to use Kirchoff's laws to find the current at each junction and then at the loops. The only deal is that I'm not sure how to handle the resistor in the middle.
     
  2. jcsd
  3. Oct 27, 2008 #2

    tiny-tim

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    Hi katrascythe! :smile:

    Your link isn't working. :cry:
     
  4. Oct 27, 2008 #3

    LowlyPion

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    Choose directions for your loop currents in each of the 2 loops. (I would choose clockwise for the top and counterclockwise for the bottom.) The voltage then of the resister in the middle represents the current of the sum of the 2 currents, top and bottom current, and becomes a term in each of your loop equations.

    You have 2 equations, 2 unknowns, solve to the bottom current and that current2 times R is your power by P = I2R.
     
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