I'm having a problem with Kirchoff's law because It seems it can be interpreted 2 ways. Perhaps they both arrive at the same answer, but if you could help me out as to which way to do it or if it matters.(adsbygoogle = window.adsbygoogle || []).push({});

1. the Integral[E*dl]=0, in a closed loop

2. the algebraic sum of the voltages in a closed loop equals zero.

The difference arrises in the sign. For instance, for the Integral[E*dl] going across a voltage source is -V because you are going against the electric field. But for the algebraic sum of voltages you are going to a higher potential so it is +V. Similarly for resitors the electric field (Integral[E*dl]) gives a +V, but for algebraic sum of voltages it is -V because there is a loss in potential. I don't understand I have never heard a explanation for this in my EE circuits class or physics class. What do you think?

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# Kirchoff's Law

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