Kirchoff's loop rule

  • Thread starter Sastronaut
  • Start date
  • #1
68
0

Homework Statement



Compute the current through R2 of the circuit in the figure.

Homework Equations


kirchoff's loop rule
V=IR


The Attempt at a Solution


Junction: I1+I2=I3

Alpha loop: V1-I3R3-I5R5=0
I1=(V1-I5R5)/R3=?

Beta loop: V2-I8R8-I5R5=0

*without one of the currents provided I am not exactly sure where to proceed from here...any help would be greatly appreciated! Anything that is a different color than black in the figure is what I added to the circuit diagram! Thank You PF!
 

Attachments

  • physics.jpg
    physics.jpg
    25.3 KB · Views: 368

Answers and Replies

  • #2
Pythagorean
Gold Member
4,292
278
You have two of the currents (in terms of other variables) so you can find the third.
 
  • #3
68
0
I have been trying to figure out the algebra but I am always left with two variable (grouping of I1, I2, or I3). I am not sure how I can get it down to just one variable for current...
 
  • #4
Pythagorean
Gold Member
4,292
278
start here:

I3 = I1 + I2

and you know what I1 and I2 are, yeah? So....

I3 = ?
 
  • #6
Pythagorean
Gold Member
4,292
278
I'm not sure what you did there... I1 and I2 will be in terms of I3 and your knowns.

Actually, I'm not quite sure what you did for your alpha/beta loops either. There is no I5 or R5 or I8/R8. Don't try to plug in your values yet, just use the names of the constants.
 
  • #7
68
0
I think I figured it out I have a value of 1.076A through R2. really appreciate the help :)
 

Related Threads on Kirchoff's loop rule

  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
1
Views
5K
Replies
11
Views
3K
Replies
5
Views
33K
Replies
2
Views
3K
  • Last Post
Replies
2
Views
804
Replies
6
Views
3K
  • Last Post
Replies
1
Views
8K
  • Last Post
Replies
6
Views
7K
  • Last Post
Replies
1
Views
2K
Top