Kirchoff's loop rule

  • Thread starter Sastronaut
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  • #1
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Homework Statement



Compute the current through R2 of the circuit in the figure.

Homework Equations


kirchoff's loop rule
V=IR


The Attempt at a Solution


Junction: I1+I2=I3

Alpha loop: V1-I3R3-I5R5=0
I1=(V1-I5R5)/R3=?

Beta loop: V2-I8R8-I5R5=0

*without one of the currents provided I am not exactly sure where to proceed from here...any help would be greatly appreciated! Anything that is a different color than black in the figure is what I added to the circuit diagram! Thank You PF!
 

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  • #2
Pythagorean
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You have two of the currents (in terms of other variables) so you can find the third.
 
  • #3
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I have been trying to figure out the algebra but I am always left with two variable (grouping of I1, I2, or I3). I am not sure how I can get it down to just one variable for current...
 
  • #4
Pythagorean
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start here:

I3 = I1 + I2

and you know what I1 and I2 are, yeah? So....

I3 = ?
 
  • #5
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I3=(-5v+(5ΩI8))/-8Ω

?????
 
  • #6
Pythagorean
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I'm not sure what you did there... I1 and I2 will be in terms of I3 and your knowns.

Actually, I'm not quite sure what you did for your alpha/beta loops either. There is no I5 or R5 or I8/R8. Don't try to plug in your values yet, just use the names of the constants.
 
  • #7
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I think I figured it out I have a value of 1.076A through R2. really appreciate the help :)
 

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