Q) Given R1=10 Ohms, R2=15 Ohms, R3=5 Ohms, find the current going through each resistor in this pathway in the attached circuit diagram.(adsbygoogle = window.adsbygoogle || []).push({});

My solution is as follows.. i'd appreciate it if you guys could verify if its correct or not:

I2=I1+I3-------------------------Equation 1

Starting from a and going through loop agdf:

-E1+I2R2+I1R1=0

15I2+10I1=6 -----------------Equation 2

Starting from k and going through loop kmdl:

-I3R3-I2R2+E2=0

-5I3-15I2=-3--------------------Equation 3

Plugging Equation 1 into Equation 2

15I2+10(I2-I3)=6

25I2-10I3=6--------------------Equation 4

Adding Equation 3 and Equation 4

25I2 - 10I3= 6

-15I2 - 5I3=-3

By multiplying equation 4 by 2 and then subtracting both, I get:

55I2=12

I2= .218A

Plugging this value of I2 into Equation 4:

25I2-10I3=6

25(.218) - 10I3=6

-10I3=.55

I3= -0.055A

Plugging I2 and I3 into Equation 1

I2=I1+I3

I1=I2-I3

I1= (.218A)-(-0.055A) = .273A

Therefore, I1= 0.273A

I2= 0.218A

I3= -0.055A

Thanks much.

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