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Physics
Quantum Physics
Klein-Gordon Equation: Forming a Conservation of Charge
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[QUOTE="TimeRip496, post: 5549074, member: 536130"] Suppose φ is solution to Klein-Gordon equation, Multiplying it by -iφ* we get [itex]iφ^*\frac{\partial^2φ}{\partial t^2}-iφ^*∇^2φ+iφ^*m^2=0[/itex] .....(5) Taking the complex conjugate of the Klein-Gordon equation and multiplying by -iφ we get [itex]iφ\frac{\partial^2φ^*}{\partial t^2}-iφ∇^2φ^*+iφm^2=0[/itex]].....(6) If we subtract the second from the first we obtain [itex]\frac{\partial}{\partial t}[i(φ^*\frac{\partial φ}{\partial t}-φ\frac{\partial φ^*}{\partial t})]+ ∇. [-i(φ^*∇φ-φ∇φ^*)]=0[/itex]...(7) This has the form of an equation of continuity [itex]\frac{\partial p}{\partial t}+ ∇.j = 0[/itex].....(8) Source: [URL]https://www2.warwick.ac.uk/fac/sci/physics/staff/academic/boyd/stuff/dirac.pdf[/URL] Qns 1: What does it means to have the complex conjugate of the KL equation? I know we obtain eqn(5) by multiplying the KL eqn with -iφ*, so that we can get the probability but why do we need to come up with the complex conjugate of the KL eqn which lead us to eqn(6)? Qns 2:Subsequently what is the rationale behind subtracting the second from the first to get eqn (7)? Qns 3: Isn't eqn(8) conservation of charge? How does it relates to the KL eqn which is obtain from the energy-momentum conservation eqn? [/QUOTE]
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Quantum Physics
Klein-Gordon Equation: Forming a Conservation of Charge
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