Hello! So in the Klein-Gordon equation you have a field ##\phi## which becomes an operator in QFT and when you apply it on the vacuum state ##|0>## you get a particle at position x: ##\hat{\phi}(x)|0>=|x>##. So if you look at this particle (in a non interaction theory) the wave function of this particle is a delta function (as you know it's exact position where it was created)? Also if you let the system evolve for a long amount of time, will the wavefunction of this particle turn into a free wave, as there is no potential, so it is basically a free particle? And if you apply the KG operator at the same initial position as before, you don't have 2 particles at position x, you have 1 particle localized at x and the other one (the first one) spread in space, is this right? Also the particle created is a spin 0 particle? Thank you!(adsbygoogle = window.adsbygoogle || []).push({});

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# I Klein-Gordon in QFT

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