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For the above problem. A helpful yahoo user told me that I can prove the answer for the above question by solving the problem. He said:

Total current is 9/6.2 = 1.45 amps.

that all flows thru the 5Ω, and 3/5 of that goes thru the 2Ω (0.87) and 2/5 thru the 3Ω (0.58).

So I understand how to prove that his ratio is correct with Korkhoff's loop rule.

But I was wondering how he got the ratio 3/5 for the current of the 2Ω and 2/5 for the 3Ω resistors without using the loop rule. Is it just intuitive?

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# Homework Help: Korkhoff's loop rule

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