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KVL and KCL problem

  1. Oct 20, 2013 #1
    1. The problem statement, all variables and given/known data

    Use Kirchhoff's voltage and current laws to find the voltage V0


    2. Relevant equations

    KVL: ƩV=0
    KCL: iin=iout

    3. The attempt at a solution

    http://s2.postimg.org/6b2013cbt/001.jpg [Broken]

    If you guys want the original circuit diagram, i'll post it.
    Note: The current flowing through i2 is -0.2mA. Forgot to put the minus sign.
     
    Last edited by a moderator: May 6, 2017
  2. jcsd
  3. Oct 20, 2013 #2

    gneill

    User Avatar

    Staff: Mentor

    You only need enough KVL loops to "touch" each component once. Any additional loops will just be dependent upon the one's you've already written. So you can stop with the first two loops equations that you wrote (I and II). That plus your KCL equation are sufficient.

    Replace VA in equation II with i1*4k. Solve for i3.
     
  4. Oct 20, 2013 #3
    I did the following:
    KCL at a: i1-i2-i3=0
    KVL at I: 4ki1+6ki2=6
    KVL at II: 16ki1-6ki2+12ki3=0 (VA=4ki1, 4VA=16ki1)
    The answers i got:
    i1=0.45mA
    i2=0.7mA
    i3=-0.2mA
     
  5. Oct 20, 2013 #4

    gneill

    User Avatar

    Staff: Mentor

    I'm seeing -(1/4) mA for i3. Maybe check your math?
     
  6. Oct 20, 2013 #5
    Maybe yeah. The calculator is showing only one significant digit.
     
    Last edited: Oct 20, 2013
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