# KVL and KCL problem

sevag00

## Homework Statement

Use Kirchhoff's voltage and current laws to find the voltage V0

KVL: ƩV=0
KCL: iin=iout

## The Attempt at a Solution

http://s2.postimg.org/6b2013cbt/001.jpg [Broken]

If you guys want the original circuit diagram, i'll post it.
Note: The current flowing through i2 is -0.2mA. Forgot to put the minus sign.

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## Answers and Replies

Mentor
You only need enough KVL loops to "touch" each component once. Any additional loops will just be dependent upon the one's you've already written. So you can stop with the first two loops equations that you wrote (I and II). That plus your KCL equation are sufficient.

Replace VA in equation II with i1*4k. Solve for i3.

sevag00
I did the following:
KCL at a: i1-i2-i3=0
KVL at I: 4ki1+6ki2=6
KVL at II: 16ki1-6ki2+12ki3=0 (VA=4ki1, 4VA=16ki1)
The answers i got:
i1=0.45mA
i2=0.7mA
i3=-0.2mA

Mentor
I'm seeing -(1/4) mA for i3. Maybe check your math?

sevag00
Maybe yeah. The calculator is showing only one significant digit.

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