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KVL and KCL problem

  • Thread starter sevag00
  • Start date
  • #1
80
1

Homework Statement



Use Kirchhoff's voltage and current laws to find the voltage V0


Homework Equations



KVL: ƩV=0
KCL: iin=iout

The Attempt at a Solution



http://s2.postimg.org/6b2013cbt/001.jpg [Broken]

If you guys want the original circuit diagram, i'll post it.
Note: The current flowing through i2 is -0.2mA. Forgot to put the minus sign.
 
Last edited by a moderator:

Answers and Replies

  • #2
gneill
Mentor
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2,773
You only need enough KVL loops to "touch" each component once. Any additional loops will just be dependent upon the one's you've already written. So you can stop with the first two loops equations that you wrote (I and II). That plus your KCL equation are sufficient.

Replace VA in equation II with i1*4k. Solve for i3.
 
  • #3
80
1
I did the following:
KCL at a: i1-i2-i3=0
KVL at I: 4ki1+6ki2=6
KVL at II: 16ki1-6ki2+12ki3=0 (VA=4ki1, 4VA=16ki1)
The answers i got:
i1=0.45mA
i2=0.7mA
i3=-0.2mA
 
  • #4
gneill
Mentor
20,793
2,773
I'm seeing -(1/4) mA for i3. Maybe check your math?
 
  • #5
80
1
Maybe yeah. The calculator is showing only one significant digit.
 
Last edited:

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