1. The problem statement, all variables and given/known data In the circuit shown in the figure, find (a) the current in resistor R; (b) the resistance R; (c) the unknown emf E. (d) If the circuit is broken at point x, what is the current in the 28v battery? 2. Relevant equations KVL and KCL 3. The attempt at a solution I don't know if these are correct :S KVL: 3(6) + 6(4) - E = 0 E = 42v So my E will be 42 volts? And in question (a) since 6A will pass in node a and the current in I2 is 4A, then logically, the remaining 2A will flow through R. So the current in R will be 2 Amperes. So now I can solve for the Resistance in R (question B) 4(6) - 48 - 28 + 2(R) = 0 24 - 48 - 28 = -2(R) R = 26 ohms Are my solutions correct? In question D, the current will be 2A if the circuit is broken at point x. Correct me if I'm wrong. Thanks in advance!