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KW to kWh

  1. Jun 1, 2017 #1
    1. The problem statement, all variables and given/known data

    If I calculate that a motor needs 41kW continuously throughout a day to run, and it costs $0.08 per kWh to run, to calculate the cost of this for 32 weeks, I would do 41 x 24hours x 7days x 32weeks x $0.08 = $17633.28

    is this a correct way of working it out?
     
  2. jcsd
  3. Jun 1, 2017 #2

    Mark44

    Staff: Mentor

    Your number is are correct, but your units don't make any sense.

    Here's what you should have, including the appropriate units.
    ##41 kW \times 24 \frac{\text{hours}}{\text{day}} \times 7 \frac{\text{days}}{\text{week}} \times 32 \text{weeks} \times .08 \frac{$}{\text{kWh}} = $17,633.28##.
    The day units cancel, the week units cancel, and the kWh units cancel, so you're left with dollar units.
    41 kW times 1 hour = 41 kWh, or 1 kW times 41 hours = 41 kWh, as well.
     
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