L2 transformation reduces to the L1 transformation

  • #1
Pyrokenesis
19
0
Hello.

I am having trouble answering the following question:

"Show that the L2 transformation reduces to the L1 transformation when the two reference frames are in standard configuration."

Am I wrong to assume that r = xi + yj + zk

Any help would be beautiful!

Thanx much
 

Answers and Replies

  • #2
mathman
Science Advisor
8,059
539
"Show that the L2 transformation reduces to the L1 transformation when the two reference frames are in standard configuration."

I assume that the source of this question defines what the L2 and L1 transformations are, as well as what two reference frames are being compared. Please elaborate.
 
  • #3
Pyrokenesis
19
0
The L2 transformations are as follows:

r' = r + γv^[(1 - 1/γ)(r.v^) - βct];

ct' = γ(ct - r.β);

where β = v/c & v^ is the unit vector in the direction of v.

The L1 transformations are:

x' = γ(x - βct);
y' = y;
z' = z;

ct' = γ(ct - βx);

where β = v/c.

All are viewed in the S' frame.
 
  • #4
HallsofIvy
Science Advisor
Homework Helper
43,010
969
We should also require that you define "standard configuration" but I'm going to assume that is with both reference frames moving in the direction of the x-axis :smile:.

Yes, you are correct to right r= xi+ yj+ zk. Notice that the difference is that "xi+ yj+ zk" assumes some particular coordinate system ("standard configuration") while "r" does not.

You may also assume ("standard configuration") that v= vi+ 0j+ 0k and that v^= i+ 0j+ 0k.
 
  • #5
Pyrokenesis
19
0
Sorry. Yes standard configuration is when both reference frames move in the direction of the x-axis.

Thanks I think I can solve it now.
 

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