Ladder Equilibrium Problem

  • Thread starter azwraith69
  • Start date
  • #1
azwraith69
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Homework Statement


see the attachment below...


Homework Equations


net force = 0, net torque = 0
normal force(ground) = ?

The Attempt at a Solution


well, so far,,

net force(y) = normal force(floor) - weight(man) - weight(ladder) + ??(force exerted by hinge?)
net force(x) = 0 ( ?? )

Choosing the bottom of ladder as pivot point,
net torque = weight(ladder) x 2a + weight(man) x a - ??(force by hinge?)




First of all, sorry for not using latex..

The hinge is my problem, since I'm not familiar in solving with it.
What are the forces (and their directions) exerted on the ladder at the hinged point?
I really don't know..

And are my assignment of forces correct?

Thanks in advance..

I NEED THIS AFTER 10 HOURS...
So i have no time to reply, so please, I'm begging, please be direct to the point. And i hope each reply will help me..

Thank you guys..
 

Attachments

  • ladder problem.pdf
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Answers and Replies

  • #2
Doc Al
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Hint: Choose a pivot point that eliminates having to know anything about the forces at the hinge.
 
  • #3
azwraith69
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Hint: Choose a pivot point that eliminates having to know anything about the forces at the hinge.

thanks... i overlooked it since i always choose the point of contact with the ground as the pivot..

normal force = 150N ??

:)
 
  • #4
Doc Al
Mentor
45,433
1,886
You got it. :approve:
 

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