A uniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. The ladder weighs 160 N. The coefficient of static friction between the foot of the ladder and the ground is 0.40. A man weighing 740 N climbs slowly up the ladder.(adsbygoogle = window.adsbygoogle || []).push({});

a) What is the maximum frictional force that the ground can exert on the ladder at its lower end?

**This is what I did: (160N + 740N) x 0.4 = 360 N

b) What is the actual frictional force when the man has climbed 1.0 m along the ladder?

**For x = 1.0 m: {(160)(1.0) + (740)(1)(1/2.5)}/ (5)(2/2.5) = ? NB

c) How far along the ladder can the man climb before the ladder starts to slip?

**(160)(2.5)(1.5/5) + (740)(1.5/2.5) x_max = 360 and solve for x_max

Can you please check my work?

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# Homework Help: Ladder problem

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