1. Dec 8, 2004

### danja347

I need help figuring out the expression for the constant $$c_+$$
expressed in j and m in the following equation:

$$\hat J_+|Y_{jm}>=c_+|Y_{jm+1}>$$

Y is just spherical harmonics and $$\hat J_+=\hat J_x + i\hat J_y$$ is a ladderoperator.

/Daniel

2. Dec 8, 2004

### dextercioby

1.Have u tried to look it into your QM book???It's something pretty "classical".Try Cohen-Tanoudji.
2.I would have given u alink,but the server at univ texas at austin is dead.Anyway...I would have actually wanted to upload that chapter from the course,but the server wouldn't accept anything more than 50KB.

Good Luck!!

3. Dec 8, 2004

### danja347

Thanks... its all clear now! :-/

4. Dec 9, 2004

### RedX

trying to recall...oh yeah:

J+|jm>=C|j(m+1)>

J+=Jx+iJy

So taking the inner product:

<jm|J-J+|jm> = CC*<j(m+1)|j(m+1)> = CC*

J-J+=(Jx-iJy)(Jx+iJy)=JxJx+JyJy+i[Jx,Jy]=J^2 - (Jz)^2 -hJz

<jm|J-J+|jm>=<jm|J^2 - (Jz)^2 -hJz}jm>=j(j+1)h^2 -m^2 h^2 - h^2 m = CC*

So taking the square root:

C=h sqrt(j(j+1) -m^2 -m)

Last edited: Dec 9, 2004