# Lagrange eq

1. Mar 1, 2012

### matematikuvol

For functional

$$J(q_1,...,q_n)=\int^{t}_{t_0}L(q_1,...,q_n;\dot{q}_1,...,\dot{q}_n;t)$$

Why isn't $$J(q_1,...,q_n;\dot{q}_1,...,\dot{q}_n;t)$$?

2. Mar 3, 2012

### OldEngr63

I had an answer for you, but the TeX system stumped me, and I was unable to write it out. Sorry about that.

Last edited: Mar 3, 2012
3. Mar 3, 2012

### Dickfore

J is a functional, and not a function of the q's. It should be written as:
$$J[q_1(t), \ldots, q_n(t)]$$