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Lagrange eq

  1. Mar 1, 2012 #1
    For functional

    [tex]J(q_1,...,q_n)=\int^{t}_{t_0}L(q_1,...,q_n;\dot{q}_1,...,\dot{q}_n;t)[/tex]

    Why isn't [tex]J(q_1,...,q_n;\dot{q}_1,...,\dot{q}_n;t)[/tex]?
     
  2. jcsd
  3. Mar 3, 2012 #2

    OldEngr63

    User Avatar
    Gold Member

    I had an answer for you, but the TeX system stumped me, and I was unable to write it out. Sorry about that.
     
    Last edited: Mar 3, 2012
  4. Mar 3, 2012 #3
    J is a functional, and not a function of the q's. It should be written as:
    [tex]
    J[q_1(t), \ldots, q_n(t)]
    [/tex]
     
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