Use lagrange multipliers to find max/min of(adsbygoogle = window.adsbygoogle || []).push({});

f(x,y)=x^2+6y

subject to

x^2-y^2=5

grad f =λgrad g

2x=2xλ, λ=1

6=-2yλ, λ=-3/y

1=-3/y, y=-3

x^2-(-3)^2=x^2-9=5

x^2=14

x=+/-√14

two points are √14, -3 and -√14, -3

plugging both points into f(x,y) gives me the same answer. now what?

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# Homework Help: Lagrange multpliers

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