- #1
Apashanka
- 429
- 15
From the invariance of space time interval the metric dΓ2=dt2-dx2-dy2-dz2
dΓ2=gμνdxμdxν
dΓ=√(gμνvμvμ)dt
dΓ=proper time.
Can someone please help me in sort out why the term √(gμνdxμdxν) is taken as the Lagrangian,as geodesic equation is solved by taking this to be the Lagrangian.
dΓ2=gμνdxμdxν
dΓ=√(gμνvμvμ)dt
dΓ=proper time.
Can someone please help me in sort out why the term √(gμνdxμdxν) is taken as the Lagrangian,as geodesic equation is solved by taking this to be the Lagrangian.