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Physics
Classical Physics
Mechanics
Lagrangian mechanics - rotating rod
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[QUOTE="BvU, post: 6499533, member: 499340"] You talk about a stationary end of rod, so you must have some specific configuration in mind. Can you divulge to us what it is ? Note that ##\int {1\over 2} {\dot r}^2 \; dm\ ## is the kinetic energy in all cases. Often it is convenient/ useful/ practical to split it up in parts, e.g. as in your c.o.m plus rotation. A force like gravity works on all ##dm## but can comfortably be considered to work on the c.o.m. that way. All in all nothing physical, just a mathematical approach :wink: ##\ ## [/QUOTE]
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Forums
Physics
Classical Physics
Mechanics
Lagrangian mechanics - rotating rod
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