1. The problem statement, all variables and given/known data Uniform chain of length L is kept of a horizontal table in such a way that l of its length keeps hanging from the table. If the whole system is in equilibrium, find the Lagrangian of the system. 2. Relevant equations Lagrangian of the system = Kinetic energy (T) - Potential energy (V) T = (mv^2)/2 V = mgh 3. The attempt at a solution In this case, V = 0 - mgl = -mgl My question is what will be the kinetic energy of the system ? I think as the system is in equilibrium, there is no motion in any portion of the chain. So, K.E. = 0 Am I wrong ?