The [itex]\Lambda[/itex] baryon (quark content [itex]uds[/itex]) decays into [itex]n + \pi^0[/itex] or [itex]p + \pi^-[/itex]. In the case [itex]\Lambda \to p + \pi^-[/itex], the [itex]s[/itex] quark decays into a [itex]u[/itex] quark, releasing a [itex]W^-[/itex] in the process (which subsequently decays into a [itex]\pi^-[/itex] meson). What happens in the [itex]\Lambda \to n + \pi^0[/itex] case? (I tried Google, but couldn't find anything about this specific decay.)(adsbygoogle = window.adsbygoogle || []).push({});

Thanks!

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# Lambda -> n + pi^0 decay

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