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Engineering
Mechanical Engineering
Laminar flow in a tube, heat transfer coefficient-sanity check
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[QUOTE="gpsimms, post: 6037533, member: 470375"] Hi there, Hopefully this is a very easy question and you all can just confirm this for me. When calculating heat transfer into a fluid from a heated tube, is it correct to say that the heat transfer coefficient is *not* dependent on the tube diameter? [ATTACH=full]229011[/ATTACH] So, if we solve for T_{out}, we get: [ATTACH=full]229012[/ATTACH] Substituting h for K*N/D, which is fluid thermal conductivity K, Nusselt number (depends on flow conditions and location in flow), and D is diameter, we get: [ATTACH=full]229013[/ATTACH] Finally, for our circular duct, A = pi*D*dx, so we get: [ATTACH=full]229014[/ATTACH] So, is there no dependence on tube diameter? I know that Nusselt number is *weakly* dependent on diameter when the flow is still developing, but that seems like it. In other words, given a large enough furnace, I could put a tube of any size in that furnace, and the flow would heat just as quickly regardless of tube diameter. That feels wrong to me, is there something I am missing? Thanks! [/QUOTE]
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Mechanical Engineering
Laminar flow in a tube, heat transfer coefficient-sanity check
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