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I did an experiment about magnetic susceptibility of [itex]Dy_2O_3[/itex] and [itex]Er_2O_3[/itex]. For data evaluation I have to calculate the theoretical Landé factor for the paramagnetic atoms in these salts which is defined as

[tex]g_j=1+\frac{j(j+1)+s(s+1)-l(l+1)}{2j(j+1)} [/tex]

where l and s are the net quantum numbers for orbital momentum and electron spin respectively, j=l+s total angular momentum. The factor gives the relation between angular momentum and magnetic momentum.

The problem is: I don't completely understand how to find the correct values for l and s. That's how I understood it:

1)l is the sum of the l values for all electrons in non-filled orbitals, and s is the sum of the spin numbers (i.e. 1/2) of all unpaired electrons. For Erbium with configuration [itex](Xe)4f^{12} 6s^2[/itex] this would then be:12 electrons in the 4f orbital, hence l=12*3, and two unpaired electrons in that orbital, i.e. s=2*1/2. Does this make sense?

2)In the crystal structure of [itex]Er_2O_3[/itex], Erbium gives away three elecrons to Oxygen. Is it then reasonable to take the electron configuration of Terbium, which is three numbers below, for the above calculation? If not, how do I have to deal with this ionic bindings?

Thanks

Bruno

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# Landé Factor

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