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## Homework Statement

Using laplace transform, solve:

[tex]

y'' - y = \frac{x^2-3x+2}{|x^2-3x+2|}[/tex]

y(0)=y'(0)=0

## Homework Equations

## The Attempt at a Solution

Just to know if I'm on the right path -

Since the quadratic has 2 roots, at 1 and at 2, the entire thing can be equal to either 1 or -1, depends on x.

So can I write it as:

[tex]y'' - y = 1 -2u_{1}(x) + 2u_{2}(x)[/tex]

?

Will this be correct?