I'm inverting this:(adsbygoogle = window.adsbygoogle || []).push({});

Y = s2 + 15s + 17 / [(s+1)(s2 + 13s - 4)]

I'm using PF expansion,

A/(s+1) + Bs + C/(s2 + 13s - 4), I however keep on getting wrong answers, seeing how Runge-Kutta and Taylor approximation disagrees with my final equation.

My final equation is:

exp(-13/2t)[19/16cosh√(185)/2t + 13√(185)/74sinh√(185)/2t] - 3/16exp(-t) = y, and it's wrong (considering Runge-Kutta and Taylor approximation disagrees with it).

Obviously, something's wrong. What did I miss? I'm starting to think that the second term is.. well, there's something wrong with it (Bs + C term). I mean, the numerator is a quadratic, therefore it can't be that simple...

NOTE: This is NOT homework. I did this to merely tickle my head. The original differential equation is y"+13y'-4y = 3exp(-t), y(0) = y'(0) = 1.

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Laplace Transform inversion

Loading...

Similar Threads - Laplace Transform inversion | Date |
---|---|

A Inverse Laplace transform of a piecewise defined function | Feb 17, 2017 |

A Inverse Laplace transform of F(s)=exp(-as) as delta(t-a) | Feb 17, 2017 |

Inverse Discrete Laplace Transform | May 28, 2015 |

Inverse Laplace transform with p^-1 and exponential | Oct 7, 2014 |

Inverse Laplace transform where e^(st)F(s) is entire | Sep 13, 2014 |

**Physics Forums - The Fusion of Science and Community**