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vela

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the farthest i got was:

=(-1/s)e^-st*sin(2t)+(1/s^2)e^-st-(cos(t)/2)-(1/s^2)sin(2t)

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vela

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What you wrote doesn't make sense to me. I'm guessing you left some stuff out. You should learn LaTeX so you can express the integrals clearly. It's pretty straightforward.

https://www.physicsforums.com/showthread.php?t=386951 [Broken]

So you started with

[tex]L[\sin 2t] = \int_0^\infty (\sin 2t)e^{-st}\,dt[/tex]

Then what?

https://www.physicsforums.com/showthread.php?t=386951 [Broken]

So you started with

[tex]L[\sin 2t] = \int_0^\infty (\sin 2t)e^{-st}\,dt[/tex]

Then what?

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Are you saying you can find the LT of sin(2t) by looking up from the table of Laplace Transforms but don't know how to derive it from the integral?

You can integrate by parts but perhaps the easiest way is to express sin(2t) in form of complex exponential using the Euler's formula.

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