# Laplace transform

1. Nov 22, 2006

### cabellos

My understanding of the laplace trasnform isnt so great so i would appreciate some help with this question please:

find the laplace transform of (t+2)sinh2t

now i know the laplace transform of sinh2t is 2/(s^2 -4) as this is a standard rule......

looking through textbooks they show the multiplication by t^n rule is needed and i found that the laplace transform of t (sin kt) = 2ks/(s^2 + k^2) ^2

how do i apply this to my equation.....

2. Nov 22, 2006

### arildno

Do not double post! :grumpy:

3. Nov 22, 2006

the Laplace transform of (t+2) is $$1/s^{2}+2/s$$

If you multiply f(t) by exp(-at) then there's a shift so F(s+a) and

$$2sinh(ax)=e^{xa}+e^{-ax}$$

then next is just hand-work...

4. Nov 22, 2006

### cabellos

thanks for the tips,

can u find the LT of 2sinh2t and the tsinh2t and add them together which gives 4/(s^2 - 4) + 4s/(s^2 + 4) ^2

is this correct?

5. Nov 23, 2006

### HallsofIvy

Yes. The definition of the Laplace tranform is:
$$L(f(t))= \int_0^\infty f(s)e^{-st}dt$$
Since
$$\int (f(x)+ g(x))dx= \int f(x)dx+ \int g(x)dx$$
It follows that you can add Laplace transforms.

It should be easy to integrate
$$\int_0^\infty (t+2)sinh t dt$$
(Break it into two integrals and use integration by parts)
as an exercise.