- #1
You are correct: it really is 2/[(s-1)(s+1)^3].I'm having trouble with this question. Can anyone please guide me.
My Attempt :
= 1/(s-1) * L{t^2*e^-t}
= 1/(s-1) * (2/(s+1)^3)
= 2/((s-1)(s+1)^3))
but that's not the answer , its 2/((s-1) s^3) somehow
If '*' means multiplication, then your answer is correct (and Maple confirms this). If '*' means 'convolution' then you answer is wrong.But on the test it says its 2/(s^3 *(s-1)), and wolfram alpha confirms it too... The question asked to find F(2).. according to my solution i will get 2/(3^3) which is 2/27 but the answer is 1/4
I agree with you; if F(s) means the product as given in the question you wrote, then F(2) = 2/27, NOT 1/4. Maybe you wrote the wrong question?In my answer which is 2/((s-1)*(s+1)^3)) , '*' does mean multiplication, so F(2) should be 2/27 , is that correct? ... test got 1/4 however.
I don't get what you did there.I'm having trouble with this question. Can anyone please guide me.
My Attempt :
= 1/(s-1) * L{t^2*e^-t}
= 1/(s-1) * (2/(s+1)^3)
= 2/((s-1)(s+1)^3))
but that's not the answer , its 2/((s-1) s^3) somehow
You still did not answer my question: you said "Wolfram Alpha gets this too...", and I essentially said I did not believe that claim; I asked you to back it up, by supplying the actual commands you gave to Wolfram Alpha. Please do this; we have tried to help you, now you can try to help us.oh wow , i get it now. Thanks you so much for helping.