1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Laplace Transformation, Translation Property

  1. Dec 6, 2009 #1
    Can anyone do a very comprehensive breakdown of the Laplace translation property for me? I don't understand how to apply it:
    L[eat f(t)] = L[f(t)] s-> s-a

    Here is a specific problem that applies it:

    1. The problem statement, all variables and given/known data

    Y(s) = 4/(s+1)3 + 1/(s+1)2 + 2/(s+1)

    I need to perform an inverse Laplace transform to find the solution to this initial value problem (beginning parts of the problem omitted).

    2. Relevant equations

    L[eat f(t)] = L[f(t)] s-> s-a


    3. The attempt at a solution

    let E = (s+1);
    L-1 (4/E3 + 1/E2 + 2/E) = 2t + t + 2

    y(t) = 2t2e-t + te-t + 2e-t

    ... but why?
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?



Similar Discussions: Laplace Transformation, Translation Property
  1. Laplace transform (Replies: 0)

  2. Laplace Transform (Replies: 0)

Loading...