I need to do a laplace transform on cos^3 t. I understand laplace but the trig is tripping me up.(adsbygoogle = window.adsbygoogle || []).push({});

cos^3 t = Cos^2 t * Cos t = cos t * (cos 2t + 1)/2 (double angle formula)

so i have (cos t)*(cos 2t)/2 + (cos t)/2.

my book's solution says (cos t)*(cos 2t)/2 = (1/2)(cos (2t+1) + cost (2t-1))... how? I cant think of any formulas that give the above result. can someone please explain?

thanks.

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# Laplace transforms on cos^3 t

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