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Laplace transforms

  1. May 10, 2010 #1
    I'm deriving the heat equation using Laplace transforms.
    I'm up to u(bar) = Aesqrt(s)x + Be-sqrt(s)x.
    My boundary conditions are lim(x tends to 0) = 0 & this makes A = 0, so u(bar) = Be-sqrt(s)x
    My other BC is ux(0,t) = -Q
    My question is how do I get B using this BC?
    I tried using the def of Laplace transforms and get -dQ(bar)/dx
     
    Last edited: May 10, 2010
  2. jcsd
  3. May 10, 2010 #2
    I got B = Q/sqrt(s) and this implies that U(bar) = Qe-sqrt(s)x/sqrt(s), I hope thats right
     
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