Solving the Differential Equation Using Laplace Transform

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In summary, the given ordinary differential equation can be solved using the laplace transform technique. After converting the equation and rearranging it, the solution is represented by Y=(s+5.2)/(s^2+4.2s+4.5). Completing the square on the denominator can simplify the solution, making it easier to convert back. There is no need for partial fraction decomposition.
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eddiej90
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Homework Statement


Using the laplace transform technique, solve the ordinary differential equation:
d2y/dt2+4.2dy/dt+4.5y=0 initial conditions: y(0)=1 and y'(0)=1


Homework Equations


From laplace tables:
d2y/dt2=s2Y-sy(0)-y'(0)
dy/dt=sY-y(0)


3. The Attempt at a Solution
After using the laplace tables to convert the equation, and rearranging it to make Y the subject, I have come to this point:
Y=(s+5.2)/s2+4.2s+4.5
Iv tried completing the square on the denominator and other methods but cannot get to a point that looks similar to the laplace tables in order to convert it back. I am pretty sure i need to use the ones under the section "General approach to quadratic functions of the form as2 + bs + c" however i have completely no idea as to what to do with α and β
 
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  • #3
Thamkyou for the link, however you cannot factorise the denominator, unless you complete the square. Can you use the partial fraction method with completing the square?
 
  • #4
eddiej90 said:
Thamkyou for the link, however you cannot factorise the denominator, unless you complete the square. Can you use the partial fraction method with completing the square?

Your denominator can certainly complete the square, s^2+4.2s+4.5=(s+2.1)^2-2.1^2+4.5, doesn't it? Obviously no need for partial fraction decomposition :biggrin:
 

1. What is the Laplace transform problem?

The Laplace transform problem is a mathematical procedure used to transform a function of a continuous variable, typically time, into a function of a complex variable, typically frequency. It is often used in engineering and physics to solve differential equations and analyze linear systems.

2. How is the Laplace transform problem solved?

The Laplace transform problem is solved by applying a specific formula, called the Laplace transform, to the original function. This formula involves integration and the complex variable s, and results in a new function of s. The inverse Laplace transform can then be applied to this new function to obtain the solution to the original problem.

3. What are the advantages of using the Laplace transform?

The Laplace transform offers several advantages, including the ability to easily solve differential equations, analyze linear systems, and handle non-zero initial conditions. It also has applications in signal processing and control theory.

4. What types of functions can be transformed using the Laplace transform?

The Laplace transform can be used on a wide range of functions, including trigonometric functions, exponential functions, and piecewise-defined functions. It is most commonly used on functions that are defined for all real numbers and have finite limits at infinity.

5. What are some real-world applications of the Laplace transform?

The Laplace transform has numerous real-world applications, such as analyzing electrical circuits, solving mechanical and structural engineering problems, and understanding the behavior of systems in control theory. It is also used in the fields of physics, chemistry, and biology to model and analyze various phenomena.

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