I have a really dumb question, but I want to make sure this is right...
So I have the integral (d2V)/(dф2) = 0. I am solving for the potential function on the bounds, 0 < ф < фo. I will also be solving on range of фo < ф < 2∏.
The Laplace equation is above.
The Attempt at a Solution
So, I am just having my doubts... When solving for 0 < ф < фo, I take the first integral with respect to d/dф, and after this I get dV/dф = arbitrary constant. If I take another integral on this (after multiplying both sides by dф), I get V = фo*arbitrary constant, right?!?
When solving for the other bounds, фo < ф < 2∏, I get V = arbitrary constant*(2∏ - фo), yes?!
Thank you for all help, I apologize for the silly question. I just wanted to make sure...