Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

I Laplacian Operator in 2D

  1. Sep 2, 2017 #1


    User Avatar

    Hi, I have that the Laplacian operator for three dimensions of two orders,

    \nabla ^2 is:

    1/r* d^2/dr^2 (r) + 1/r^2( 1/sin phi d/d phi sin phi d/d phi + 1/sin^2 phi * d^2/d theta^2)

    Can this operator be used for a radial system, where r and phi are still valid, but theta absent, by setting theta = 0 ?

    so giving:

    1/r* d^2/dr^2 (r) + 1/r^2( 1/sin phi d/d phi sin phi d/d phi) ?

    Does that make sense or is the Laplacian operator of second order in radial (polar) coordinates different?

  2. jcsd
  3. Sep 2, 2017 #2


    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Gold Member

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted

Similar Discussions: Laplacian Operator in 2D
  1. Laplacian property (Replies: 0)