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Mathematics
Differential Equations
Large oscillations of pendulum
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[QUOTE="epenguin, post: 5570207, member: 106258"] If I am not mistaken this form has different subject on the left hand side than the form I gave which was t = ... If you want to go further I am not the person to ask - but it seems he has these last minutes arrived!. :oldsmile: What I think it is useful for you to be familiar with is that an equation x'' + f(x) = 0 , which is the equation of a particle moving under a force that depends only on position in one dimension, can be reduced to t = an integral of a function of x by multiplying the equation by 2x' and then the first term is (x[SUP]2[/SUP])' . So you can get an equation with x' as LHS, and on the RHS you'll get through just an integral with respect to t of something involving a square root. By the way before square rooting this is just the energy equation. Just if you're lucky this will be an integral that corresponds to functions you know the integral of. If you're interested you could work this out for simple harmonic motion - second term kx. You should find you get the same results as what is usually done in a more direct way. You can also solve it with 'elementary' integration when the one-dimensional force is inverse square. But in other cases you may also find that the integrals are not any of the 'elementary' ones, as here. [/QUOTE]
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