1. The problem statement, all variables and given/known data A sculptor has come to you with a problem, because she knows that you are such a good physics student. She wishes to make a lead casting of an object which will require 2 kg of melted lead. If the lead was stored in her basement at approximately 55˚F, and it is to be melted in a 1/4" thick steel ladle/pot of approximate cross sectional area 12in^2, how long will it take to melt the lead if it is placed in a kiln at 617.5˚F, the melting point of lead? Lf = 0.25x10^5 J/kg Lv = 8.7x10^5 J/kg c = 130 J/kg*C˚ k = 40 J/s*m*C˚ 2. Relevant equations P = kA(ΔT/d) Q = mcΔT Q = mL P = Q/Δt 3. The attempt at a solution 12in^2 = 0.0077 m^2 55˚F = 12.7˚C 617.5˚F = 325.3˚C 0.25 in = 0.00635 m P = kA(ΔT/d) P = (40 J/s*m*C˚)(0.0077m^2)((325.3˚C-12.7˚C) / 0.00635 m) P = 15162.3 Q1 = mcΔT Q1 = (2 kg)(130 J/kg*˚C)(325.3˚C-12.7˚C) Q1 = 81276 J Q2 = mL Q2 = (2 kg)(0.25x10^5 J/kg) Q2 = 50000 J Q1+Q2 = 81276 J + 50000 J = 131,276 J P = Q/Δt 15162.3 = (131,276 J)t t = 0.1155 s So... I REALLY don't think this is correct, but I can't seem to think of another way around this. Any help would be appreciated!