1. The problem statement, all variables and given/known data 25 kg of ice at 0C is combined with 4 kg of steam at 100C. What is the final equilibrium temperature in Celsius of the system? (Lf = 3.33x 10^5 J/kg; Lv= 2.26x10^6 J/kg; 1 cal= 4.186 J) Answer: 20 2. Relevant equations mc(Tf- Ti) m(Lf) or m (Li) 3. The attempt at a solution I thought you should do an equation for both parts so: m= mass c = specific heat T= temperature mc(Tf-Ti) + m(lf) +mc(Tf-i)=0 25(2090)(Tf-0) + 25(3.33x10^6) + 25(4186)(Tf-0) = 0 then... mc(Tf-Ti) + m(Lv) +mc(Tf-i)=0 4(2010)(Tf-100)+ 4(2.26x 10^6) + 4(4186)(Tf-100) = 0 however I used these equation and solved for Tf in both and added them together to get a final answer and the answer was not 20. please help!! thanks in advanced.