Latent heat calculation!! Ok... first timer. I am not a science student, done some MBA but wanting some IT course and for entrance exam, I am preparing. I have problem with this one problem. Just provide me a hint. I do calculation part. 'Juice and water is produced from 5.0 liters of water, a temperature of 25 ° C. Ice is added of which temperature is -18 oC. How large ice cube mass should be in order to drink, the final mixing temperature is 10 ° C? Suppose to drink and the environment, there is no heat exchange. Juice and water specific heat is 4.19 kJ / (kg ° C), ice specific heat 2.2 kJ / (kg ° C) and ice latent heat is 333 kJ / kg. Juice and water density is 1.0 kg/dm3.' (i just translated this question from finnish to english, so grammar mistake is there!!) Please do provide me hints as to how I proceed with this question.