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Latent heat of fusion

  1. Jun 14, 2013 #1
    1. The problem statement, all variables and given/known data
    mass of cup 1.78g
    initial mass of water and cup - 54.26g
    finlal mass of water after ice added - 91.26g
    initial temperature - 27°C
    temperature after heated - 92°C
    temperature after ice added - 35°C

    1) how much heat energy did the original mass of water lose?
    2) what is the gain in the energy of the melted ice as its temperature rose from 0°C
    3)calculate the amount of heat energy required to melt the ice

    2. Relevant equations

    Q = mcΔθ
    Q = mLv

    3. The attempt at a solution

    1) Q= .093 × 4200×57 = 22264 J

    I am not sure if this is correct i dont know what to do for the other two including this one could someone help me please :confused:
  2. jcsd
  3. Jun 14, 2013 #2

    Andrew Mason

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    Welcome to PF Ravi.

    First you should give us the complete problem as written. There is some information missing here. What is the cup made of? Second, you must explain your reasoning and tell us where you get these numbers.

  4. Jun 14, 2013 #3
    the cup is made out of styro foam an it was an experiment an that was the results
  5. Jun 14, 2013 #4


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    How is that relevant?
    Are you sure the ice was at 0C?
    It's not at all clear where you are getting those numbers from. It's much better to do the working in symbols, only plugging in numbers at the end. At the least, please show how each of those numbers comes from your raw data.
  6. Jun 14, 2013 #5
    just please take the ice as 0°C
  7. Jun 14, 2013 #6
    an the initial temperature was 27°C of the water beforeheat was applied
  8. Jun 14, 2013 #7


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    Yes, I understand that, but I don't see how it is relevant to the questions. They all seem to concern what happened after the water had been heated.
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